A) targetIndex += 1
B) targetIndex -= 1
C) logicalSize += 1
D) logicalSize -= 1
Correct Answer
verified
Multiple Choice
A) myArray[ temp ] = myArray[ i ]
B) temp [ i ] = myArray[ i ]
C) myArray[ i ] = temp[ i ]
D) temp = myArray(len(myArray) )
Correct Answer
verified
Multiple Choice
A) overlapping
B) noncontiguous
C) sequential
D) random
Correct Answer
verified
Multiple Choice
A) sum += grid[ column ][ row ]
B) sum += grid[ row-1 ][ column-1 ]
C) sum += grid[ column+1 ][ row+1 ]
D) sum += grid[ row ][ column ]
Correct Answer
verified
Multiple Choice
A) it is less complex to implement
B) you can easily access the predecessor of an item
C) you can easily access the successor of an item
D) it uses less memory
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) probe
B) insertion
C) removal
D) traversal
Correct Answer
verified
Multiple Choice
A) deletion of an item in a linked list
B) appending an item to the end of a linked list
C) replacing an item at the beginning of a linked list
D) insertion of an item at the beginning of a linked list
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) logarithmic
B) linear
C) exponential
D) random
Correct Answer
verified
Multiple Choice
A) if myItem is Null:
B) if myItem != None:
C) if myItem = None:
D) if myItem is not Null:
Correct Answer
verified
Multiple Choice
A) myArray(10) = Array
B) Array myArray, 10
C) myArray = Array(10)
D) Array(10) myArray
Correct Answer
verified
Multiple Choice
A) sum of all items
B) replacement
C) insertion
D) deletion
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) delete the array
B) grow the array
C) reset the array
D) shrink the array
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) size
B) append
C) increase
D) augment
Correct Answer
verified
Showing 1 - 20 of 50
Related Exams